Last post wins.
11-05-2013, 09:15 AM
Post: #811
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RE: Last post wins.
Uh...
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11-05-2013, 09:18 AM
Post: #812
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RE: Last post wins.
My mistake, 1000th post of this thread is last post of page 100
I am GameCenter's Chemoeum. RIP, DL banner. Explosions. Go here! |
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11-05-2013, 09:21 AM
Post: #813
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RE: Last post wins.
I want the 1000th reply though. Not the 1000th post. And some people have a different number of posts per page
GC: Chas3r 926 |
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11-05-2013, 09:35 AM
Post: #814
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RE: Last post wins.
(11-05-2013 07:59 AM)TheGoldenGriffin Wrote: Why doesn't it have a symbol, like numbers π Φ or ∞? I think it's usually represented with the capital letter G. |
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11-05-2013, 10:11 AM
(This post was last modified: 11-05-2013 10:11 AM by Chas3r 926.)
Post: #815
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RE: Last post wins.
Yeah I think you're right
GC: Chas3r 926 |
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11-05-2013, 10:32 AM
Post: #816
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RE: Last post wins.
How does g equal g times 64? xD
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11-05-2013, 10:47 AM
Post: #817
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RE: Last post wins.
When g=1
I hear there's a secret Mobi hidden here somewhere… |
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11-05-2013, 11:28 AM
Post: #818
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RE: Last post wins.
I am GameCenter's Chemoeum. RIP, DL banner. Explosions. Go here! |
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11-05-2013, 11:46 AM
Post: #819
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RE: Last post wins.
(11-05-2013 11:28 AM)Someone21 Wrote:(11-05-2013 10:47 AM)TheGoldenGriffin Wrote: When g=1 Oops haha, that makes more sense I hear there's a secret Mobi hidden here somewhere… |
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11-05-2013, 03:25 PM
Post: #820
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RE: Last post wins.
It's not g times 64, it's a subscript. It's basically a recursively defined function. g subscript 1 equals 3↑↑↑↑3, and g subscript n is defined based upon g subscript n-1. So g subscript 64 equals 3[↑^(g subscript 63)]3, so then that's 3[↑^(3[↑^(g subscript 62)]3)]3, which expands to 3[↑^(3[↑^(3[↑^(g subscript 61)]3)]3)]3, and so on...
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