Last post wins. - Printable Version +- One Man Left Studios Community Forums (http://www.onemanleft.com/forums) +-- Forum: General (/forumdisplay.php?fid=1) +--- Forum: Poppycock (/forumdisplay.php?fid=2) +--- Thread: Last post wins. (/showthread.php?tid=89) Pages: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 |
RE: Last post wins. - Charlie12520 - 11-05-2013 09:15 AM Uh... RE: Last post wins. - Chemoeum - 11-05-2013 09:18 AM My mistake, 1000th post of this thread is last post of page 100 RE: Last post wins. - Chas3r 926 - 11-05-2013 09:21 AM I want the 1000th reply though. Not the 1000th post. And some people have a different number of posts per page RE: Last post wins. - TheGreatErenan - 11-05-2013 09:35 AM (11-05-2013 07:59 AM)TheGoldenGriffin Wrote: Why doesn't it have a symbol, like numbers π Φ or ∞? I think it's usually represented with the capital letter G. RE: Last post wins. - Chas3r 926 - 11-05-2013 10:11 AM Yeah I think you're right RE: Last post wins. - Charlie12520 - 11-05-2013 10:32 AM How does g equal g times 64? xD RE: Last post wins. - TheGoldenGriffin - 11-05-2013 10:47 AM When g=1 RE: Last post wins. - Chemoeum - 11-05-2013 11:28 AM (11-05-2013 10:47 AM)TheGoldenGriffin Wrote: When g=1 When g=0 RE: Last post wins. - TheGoldenGriffin - 11-05-2013 11:46 AM (11-05-2013 11:28 AM)Someone21 Wrote:(11-05-2013 10:47 AM)TheGoldenGriffin Wrote: When g=1 Oops haha, that makes more sense RE: Last post wins. - TheGreatErenan - 11-05-2013 03:25 PM It's not g times 64, it's a subscript. It's basically a recursively defined function. g subscript 1 equals 3↑↑↑↑3, and g subscript n is defined based upon g subscript n-1. So g subscript 64 equals 3[↑^(g subscript 63)]3, so then that's 3[↑^(3[↑^(g subscript 62)]3)]3, which expands to 3[↑^(3[↑^(3[↑^(g subscript 61)]3)]3)]3, and so on... |