Still neck division - Printable Version +- One Man Left Studios Community Forums (http://www.onemanleft.com/forums) +-- Forum: General (/forumdisplay.php?fid=1) +--- Forum: Outwitters (/forumdisplay.php?fid=11) +--- Thread: Still neck division (/showthread.php?tid=2981) |
RE: Still neck division - jchris98 - 01-16-2014 09:06 AM (01-16-2014 04:23 AM)amoffett11 Wrote: This is the same as the classic Birthday problem: given 25 people in a room, what are the odds that at least 2 of them have the same birthday. People are usually quite surprised to find that the odds are slightly higher than 50% that 2 people will be born on the same day. Are you sure? RE: Still neck division - amoffett11 - 01-16-2014 11:41 PM (01-16-2014 09:06 AM)jchris98 Wrote:(01-16-2014 04:23 AM)amoffett11 Wrote: This is the same as the classic Birthday problem: given 25 people in a room, what are the odds that at least 2 of them have the same birthday. People are usually quite surprised to find that the odds are slightly higher than 50% that 2 people will be born on the same day. Sure about what? The birthday thing? RE: Still neck division - jchris98 - 01-17-2014 02:10 AM Yeah, that doesn't sound right RE: Still neck division - lawtai - 01-17-2014 02:14 AM http://en.wikipedia.org/wiki/Birthday_problem Looks like you only need 23 people to hit 50%. RE: Still neck division - amoffett11 - 01-17-2014 02:33 AM (01-17-2014 02:14 AM)lawtai Wrote: http://en.wikipedia.org/wiki/Birthday_problem Ya, whenever I hear the example, it's always 25, but probably because that's just an even number. I remember having this discussion with my brother years and years ago, he didn't believe it either, so we started looking at baseball teams (every team 25 players on its roster), we went through about 16 teams and 10 or 11 teams already had two players with the same birthday, so we stopped. RE: Still neck division - Mag!cGuy - 01-17-2014 02:54 AM I read an article about it, and there was the mathematic proof of this, so I could only believe it RE: Still neck division - [PETA] Doodat - 01-17-2014 02:59 AM Pretty sure it's about probabilities: Need to find the percentage of no people have birthdays together (this is continuing to assume that no two people have the same birthday) For 1 person, there is 365/365 For 2 people, I would say 364/365 to keep it simple, although the fraction is much weirder than that due to leap years. 3 people: 364/365 * 363/365 4 people: 364/365 * 363/365 * 362/365 5 people: 364/365 * ... * 361/365 And so on. Even for 10 people: already ~12% chance that 2 people will have the same birthday. (because ~88% chance that they will not have the same birthday) RE: Still neck division - TheGreatErenan - 01-17-2014 03:06 AM Yes, Doodat has it right. |